Sensor type for energy metering

[Hathor27]

I'd like to read and log the amount of used electrical energy. From the sensor (energy meter) I get pulse-counts each minute.

Into which type of sensor should I log this value, for I could graph it as energy per time (rate) and/or total energy.

Further, how could I modify graphs then to display y-axis unit in kWh?...

[skyewright]

I'd like to read and log the amount of used electrical energy. From the sensor (energy meter) I get pulse-counts each minute.
Into which type of sensor should I log this value, for I could graph it as energy per time (rate) and/or total energy.
Further, how could I modify graphs then to display y-axis unit in kWh?...

For anything non-standard use the "data" sensor type. That is totally 'generic'.

Your LED pulses are probably each 1Wh (at least that's pretty standard on UK meters).

I use "deltasum" with 1 hour 'buckets" to graph the number of Wh in an hour if I'm using Meteohub graphing.

If I'm using Meteoplug then I use the equivalent graphing feature, but in Meteoplug graph defeinitions you also have the opportunity for doing some maths.
Mosyly nowadays I use Meteoplug graphs...

[Hathor27]

I use "deltasum" with 1 hour 'buckets" to graph the number of Wh in an hour if I'm using Meteohub graphing.

That's good
And how do you build the sum of the individual pulses?

[skyewright]

I use "deltasum" with 1 hour 'buckets" to graph the number of Wh in an hour if I'm using Meteohub graphing.

That's good
And how do you build the sum of the individual pulses?

The data sensor that I use this with is an accumulating counter value.

If you are just delivering pulse counts, rather than a accumulating total, then maybe you could try "sum" instead of "deltasum"?

[Hathor27]

If you are just delivering pulse counts, rather than a accumulating total, then maybe you could try "sum" instead of "deltasum"?

Thx - I will try it soon.

As I found by now, another approach would be the method I use for degree-days accumulation
(see viewtopic.php?f=16&t=8457&p=11241#p11241)